Published by:
CGP EDU Academic Team
Published on: August 13, 2026
If f : R → R is a twice differentiable function such that f ′′ (x) > 0 for all x ∈ R, and f
=
, f(1) = 1, then
Text Solution
Verified by ExpertsThe correct answer is:
B
f ′′ (x) > 0 for all x ∈ R , f(1/2) = 1/2, f(1) = 1
⇒ f ′ (x) increases
Let g(x) = f(x) – x , x ∈ [1/2,1]
Then g ′ (x) = 0 has atleast one real root in (1/2,1)
f ′ (x) = 1 has atleast one real root in (1/2,1)
Hence f ′ (x) increases ⇒ f ′ (1) > 1
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
For the function f(x) = x cos , x ≥ 1,
Let p(x) be a polynomial of degree 4 having extremum at x = 1, 2 and = 2. Then the value of p(2) …
Let f be a function defined on R (the set of all real numbers) such that
f ′ (x) = 2010 (x – 2009) …
Let f, g and h be real-valued functions defined on the interval [0, 1] by f(x) = + , g(x) = + …
Match the statements given in Column-I with the intervals/union of intervals given in Column-II
Col…
The number of distinct real roots of x 4 – 4x 3 + 12x 2 + x – 1 = 0 is
< f ′ (1) ≤ 1