Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The normal to the curve y(x – 2)(x – 3) = x + 6 at the point where the curve intersects the y-axis passes through the point :
Text Solution
Verified by ExpertsThe correct answer is:
B
y(x –2) (x–3) = x + 6
Intersection with y-axis ;
Put x = 0 ⇒ y = 1
⇒ Point of Intersection is (0, 1)
Now vc , y = 
y' = 
y' =
= 1 at (0,1)
∴ Equation of normal is given by
(y –1) = –1 (x – 0)
x + y –1 = 0
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Given P(x) = x 4 + ax 3 + bx 2 + cx + d such that x = 0 is the only real root of P ′ (x) = 0. If P(…
The shortest distance between the line y – x = 1 and the curve x = y 2 is
Let f : R → R be defined by
f(x) =
If f has a local minimum at x = – 1, then a possible value of k…
Let f : R → R be a continuous function defined by f(x) =
Statement -1 : f(c) = , for some c ∈ R.
…
The equation of the tangent to the curve y = x + , that is parallel to the x-axis,
Let f be a function defined by -
f(x) =
Statement - 1 : x = 0 is point of minima of f
Statement - …