The radius of a circle, having minimum area, which touches the curve y = 4 – x 2 and the lines, y = |x| is
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let radius of circle be r, its center lies on y-axis as y-axis bisects the 2 rays of y = |x|
Now vc 4 –
⇒ 
Note : The correct solution should be

due to symmetry center of the circle must be on y-axis
let center be (0, k)
Length of perpendicular from (0, k) to y = x,
(0, k) ls y = x
i.e. r = 
∴ Equation of circle x 2 + (y – k) 2 = 
solving circle and parabola 4 – y + y 2 – 2ky +
= 0
y 2 – (2k + 1) y +
= 0
Because circle touches the parabola D
D = 0
(2k + 1) 2 = 4 
4k 2 + 4k + 1 = 2k 2 + 16
On solving we get k = 
Therefore radius k =
≈ 1.3546
However among the given choices the following method will yield one of the choice.
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