Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Let ƒ : R → R be a function such that ƒ
=
for all x and y, and ƒ(0) = 3 and ƒ ′ (0) = 3. Then -
Text Solution
Verified by ExpertsThe correct answer is:
B
ƒ(x + h) =
ƒ
=
[ƒ(2x) + ƒ(2h)]
=
ƒ (2x) +
ƒ(2h) =
ƒ(2x) +
ƒ(0)
(ƒ is differentiable at 0 so continuous also )
Putting y = 0 in the given equation, we have
ƒ(x) = ƒ
= 
Hence
ƒ(x + h) = ƒ(x)
Since ƒ(x)/x is not defined at x = 0, ƒ(x)/x is not continuous on R. Clearly ƒ(x) need not be bounded on R. e.g. ƒ(x) = x .
ƒ satisfies the given equation but is not bounded on R.
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