A point where function ƒ(x) is not continuous where ƒ(x) = …

Maths Functions, Limits, Continuity and Differentiability General Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: August 13, 2026

A point where function ƒ(x) is not continuous where ƒ(x) = [sin [x]] in (0, 2 π ) [.] denotes greatest integer ≤ x is -

(3, 0)

(2, 0)

(1, 0)

None of these

Text Solution

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The correct answer is:

For 0 ≤ x < 1, ƒ(x) = [sin x] = 0

1 ≤ x < 2, f(x) = [sin 1] = 0

2 ≤ x < 3, f(x) = [sin 2] = 0

3 ≤ x < 4, f(x) = [sin 3] = 0

Hence there is discontinuity at point (4, –1).

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