Home Maths Permutations & Combination NTA Abhiyas Question The number of eight-digit integers, with the…
Maths Permutations & Combination NTA Abhiyas Question Single Correct MCQ
Published on: August 13, 2026

The number of eight-digit integers, with the sum of digits equal to 12 and formed by using the digits 1, 2 and 3 only are

A
255
B
277
C
288
D
266

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Text Solution

Verified by Experts
The correct answer is:
D

266

The desired number is the coefficient of x 12 in (x + x 2 + x 3 )

= coefficient of x 12 in x 8 (l + x + x 2 ) 8

= coefficient of x 4 in

= coefficient of x 4 in (l + x 3 ) (1 -x) -8

= coefficient of x 4 in (l - 8x 3 +. ... ) (1 - x) -8

= coefficient of x 4 in (1 - x) -8 - 8x coefficient of x in (1- x) -8

= 4+8-1 C 8-1 -8x+ 1+8-1 C 8-1

= 11 C 7 -8x 8 C 7 =

= 330 - 64 = 266

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