Home Maths Permutations & Combination NTA Abhiyas Question The number of ways in which 10 boys can be d…
Maths Permutations & Combination NTA Abhiyas Question Single Correct MCQ
Published on: August 14, 2026

The number of ways in which 10 boys can be divided into 2 groups of 5, such that two tallest boys are in two different groups, is equal to

A
70
B
35
C
252
D
126

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Text Solution

Verified by Experts
The correct answer is:
A

70

Excluding the 2 tallest boys, we can divide the 8 boys into 2 groups of 4 each by

The tallest boys can be assigned to the groups in 2 ways.

The desired number of ways are

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