If x = 3 is the chord of contact of the circle x 2 + y 2 = …

Maths Circle and System of Circles NTA Abhiyas Question Single Correct MCQ

Published on: August 14, 2026

If x = 3 is the chord of contact of the circle x 2 + y 2 = 81, then the equation of the corresponding pair of tangents, is

x 2 - 8y 2 + 54x + 729 = 0

x 2 - 8y 2 - 54x + 729 = 0

x 2 - 8y 2 - 54x - 729 = 0

x 2 - 8y 2 = 729

Text Solution

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The correct answer is:

x 2 - 8y 2 - 54x + 729 = 0

Put x = 3 in the equation of circle to get the point of contact,

Hence, equation of the pair of tangents is

(3x + 6 y -81) (3x - 6 y - 81) = 0

(x-27) 2 -8y 2 =0

x 2 - 54x - 8y 2 + 729 = 0

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