Home Maths Circle and System of Circles NTA Abhiyas Question If the circles x 2 + y 2 -10x + 16y + 89 - r…
Maths Circle and System of Circles NTA Abhiyas Question Single Correct MCQ
Published on: August 14, 2026

If the circles x 2 + y 2 -10x + 16y + 89 - r 2 = 0 and x 2 + y 2 + 6x - 14y + 42 = 0 have common points, then the number of possible integral values of r is equal to

A
13
B
14
C
15
D
18

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The correct answer is:
D

18

Centre & radius of x 2 + y 2 - 10x + 16y + 89 - r 2 = 0 are (5, -8) &| r| respectively

Centre & radius of x 2 + y 2 + 6x - 14y + 42 = 0 are (-3,7) & 4 respectively

Distance between the centres of circles is

17-4 |r| 17 + 4

13 r 21

r {± 21, ±20, ±19, ±18, ±17, ±16, ±15, ±14, ±13}

Hence, the number of possible values of r is equal to 18

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