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CGP EDU Academic Team
Published on: August 14, 2026
The curve y(x) = ax 3 + bx 2 + ex + 5 touches the x-axis at the point P(-2, 0) and cuts the y-axis at the point Q, where y' is equal to 3. Then the local maximum value of y(x) is :
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
y(x) = ax 3 + bx 2 + ex + 5 is passing through
(-2,0) then 8a-4b + 2c = 5......(1)
y'(x) = 3ax 2 + 2bx + c touches x-axis at (-2,0)
12a-4b + c = 0 ......(2)
again, for x= 0, y'(x) = 3
c = 3 ..(3)
Solving eq. (1), (2) & (3) a = 
, b = 
y(x) has local maxima at x = 1
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