Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Let ω be a complex number such that 2ω + 1 = z where z = 
. If 
= 3k, then k is equal to:
Text Solution
Verified by ExpertsThe correct answer is:
A
z = 
⇒ 2ω + 1 = 
i
2ω = 
i – 1
ω = 
⇒ 1 + ω + ω 2 = 0 & ω 3 = 1
⇒ 
= 3k
⇒ 
= 3k
3(ω 2 – ω 4 ) = 3k
k = ω 2 – ω = 
– 
= – 
– 
= – 
= – z
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