Section 2 (Maximum Marks: 18)
• This section contains SIX (06) questions. The answer to each question is a NUMERICAL VALUE.
• For each question, enter the correct numerical value of the answer using the mouse and the on-screen virtual numeric keypad in the place designated to enter the answer. If the numerical value has more than two decimal places, truncate/round-off the value to TWO decimal places.
• Answer to each question will be evaluated according to the following marking scheme.
Full Marks : +3 If only the correct numerical value is entere(d)
Zero Marks : 0 In all other cases.
Suppose a 
nucleus at rest and in ground state undergoes 
-decay to a 
nucleus in its excited state. The kinetic energy of the emitted a particle is found to be 4.44 MeV. 
nucleus then goes to its ground state by y-decay. The energy of the emitted y photon is_____ keV.
[Given: atomic mass of 
= 226.005 u, atomic mass of 
= 222.000 u, atomic mass of a particle = 4.000 u, 1 u = 931 MeV/c 2 , c is speed of the light]
Text Solution
Verified by Experts135
(135)
Total energy emitted = ( 
m)C 2
= 0.005 x 931.5 MeV = E 0 (say) ... (i)
Also, 
= 4.44 MeV ...(ii)
E Rn = 4.44MeV x 
...(iii)
E r = E 0 -E a -E Rn =135keV
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