Home Maths JEE - Advanced Previous Year Paper JEE-Advanced-2019-Paper-2 SECTION 3 (Maximum Marks: 12) • This section…
Maths JEE - Advanced Previous Year Paper JEE-Advanced-2019-Paper-2 Single Correct MCQ
Published on: August 13, 2026

SECTION 3 (Maximum Marks: 12)

• This section contains TWO (02) questions.

• Each List-Match set has TWO (02) Multiple Choice Questions.

• Each List-Match set has two lists: List-I and List-II.

• List-I has Four entries (I), (II), (III) and (IV) and List-II has Six entries (P), (Q), (R), (S), (T) and (U).

• FOUR options are given in each Multiple Choice Question based on List-1 and List-II and ONLY ONE of these four options satisfies the condition asked in the Multiple Choice Question.

Answer to each question will be evaluated according to the following marking scheme:

Full Marks : +3 If ONLY the option corresponding to the correct combination is chosen.

Zero Marks : 0 If none of the options is chosen (i.e. the question is unanswered).

Negative Marks : -1 In all other cases.

Answer the following by appropriately matching the lists based on the information given in the paragraph

Consider the Bohr's model of a one-electron atom where the electron moves around the nucleus. In the following, List-I contains some quantities for the n th orbit of the atom and List-II contains options showing how they depend on n.

LIST-I LIST-II

(I) Radius of the n th orbit (P)

(II) Angular momentum of the electron in the n th orbit (Q)

(III) Kinetic energy of the electron in the n th orbit (R)

(IV) Potential energy of the electron in the n th orbit (S)

(T)

(U)

(i) Which of the following options has the correct combination considering List-I and List-II? Options

A
(III), (P) (I), (T)
B
(IV), (U) (II), (R)
C
(III), (S) (I),(P)
D
(IV), (Q) (ii) Which of the following options has the correct combination considering List-I and List-II? Options (II), (Q)

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Text Solution

Verified by Experts
The correct answer is:
CHECK THE SOLUTION.

(i)

(ii)

Sol (i)-(ii).

Radius =

Angular momentum of electron (mvr) =

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