Home Maths JEE - Advanced Previous Year Paper JEE-Advanced-2020-Paper-2 PART III: MATHEMATICS SECTION 1 (Maximum Mar…
Maths JEE - Advanced Previous Year Paper JEE-Advanced-2020-Paper-2 Numeric Response
Published on: August 11, 2026

PART III: MATHEMATICS

SECTION 1 (Maximum Marks: 18)

• This section contains SIX (06) questions.

• The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 TO 9, BOTH INCLUSIVE.

• For each question, enter the correct integer corresponding to the answer using the mouse and the on-screen virtual numeric keypad in the place designated to enter the answer.

• Answer to each question will be evaluated according to the following marking scheme:

Full marks : +3 If ONL Y the correct integer is entered;

Zero Marks : 0 If the question is unanswered;

Negative Marks : -1 In all other cases.

For a complex number z, let Re(z) denote the real part of z. Let S be the set of all complex numbers z satisfying z 4 - |z| 4 = 4 i z 2 , where i = . Then the minimum possible value of |z 1 - z 2 | 2 , where z 1 , z 2 S with Re(z 1 ) > 0 and Re(z 2 ) < 0, is_____

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Text Solution

Verified by Experts
The correct answer is:
8

(8)

z 4 - |z| 4 = 4i z 2 z

4 -z 2 - =4iz 2 z

2 = 0 or z 2 - =4i

Let z = x + iy

(z + )(z- ) = 4i

2x.2iy = 4i

xy= 1

z 1 lies on xy = 1 in first quadrant and z 2 lies on xy = 1 in third quadrant.

|z 1 - z 2 | 2 is minimum when z 1 = (1, 1) and z 2 = (-1, -1)

|z 1 - z 2 | 2 = 8

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