Home Maths JEE - Advanced Previous Year Paper JEE-Advanced-2020-Paper-2 Section 3 (Maximum Marks: 24) • This section…
Maths JEE - Advanced Previous Year Paper JEE-Advanced-2020-Paper-2 Numeric Response
Published on: August 12, 2026

Section 3 (Maximum Marks: 24)

• This section contains SIX (06) questions. The answer to each question is a NUMERICAL VALUE.

• For each question, enter the correct numerical value of the answer using the mouse and the on-screen virtual numeric keypad in the place designated to enter the answer. If the numerical value has more than two decimal place, truncate/round-off the value to TWO decimal places.

• Answer to each question will be evaluated according to the following marking scheme:

Full marks : +4 If ONLY the correct numerical value is entered;

Zero Marks: 0 In all other cases.

An engineer is required to visit a factory for exactly four days during the first 15 days of every month and it is mandatory that no two visits take place on consecutive days. Then the number of all possible ways in which such visits to the factory can be made by the engineer during 1-15 June 2021 is_____

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Text Solution

Verified by Experts
The correct answer is:
495.00

(495.00)

We need to put 4 stick (identical) between 11 balls (identical) such that no 2 stick are together

12 C 4 = 495

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