In a photoemission experiment, the maximum kinetic energies of photoelectrons from metals P, Q and R are E P , E Q and E R , respectively, and they are related by E P = 2E Q = 2E R . In this experiment, the same source of monochromatic light is used for metal P and Q while a different source of monochromatic light is used for the metal R. The work functions for metals P, Q and R are 4.0 eV, 4.5 eV and 5.5 eV, respectively. The energy of the incident photon used for metal R, in eV, is______.
Text Solution
Verified by Experts6
(6)
Let E R = E
Then E Q = E
E P = 2E
From Einstein's equation for P, Q and R
2E = hv-4.0 ...(i)
E = hv-4.5 ...(ii)
E = hv'-5.5 ...(iii)
Solving equation (i) and (ii) we get E = 0.5
So, hv' = 6.0 eV
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