SECTION 3
• This section contains TWO (02) paragraphs. Based on each paragraph, there are TWO (02) questions.
• Each question has FOUR options
Text Solution
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(i) (ii)
(i) As S character increases bond dissociation energy increases
H-C = CH H-CH = CH 2
sp sp 2
H-CH(CH 3 ) 2 H-CH 2 -Ph
sp 3 sp 3
And
is more stable then 
(ii) CH 4 + C1 2
CH 3 C1 + HC1 this reaction is obtained from given reaction.
CH 3 -H
...(1)
C1-C1
...(2)
CH 3 -Cl
...(3)
H-C1
...(4)
(1) + (2)-(3)-(4)
Hence
H-105+ 58-85-103--25 KCal/mole
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H° = -58 kcal mol -1 .
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