Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Prove that
(i) 
+ 
+ 
= 1
(ii) (log 2 10) (log 2 80) – (log 2 5) (log 2 160) = 4
(iii) 
= 
(iv) 
= a 2 + a + 1
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(i) L.H.S. = log abc 
+ log abc 
+ log abc 
= log abc 
= 1= R.H.S.
(ii) (1 + log 2 5) (4 + log 2 5) – (log 2 5) (5 + log 2 5) = 4 + (log 2 5) 2 + 5(log 2 5) –5log 2 5 – (log 2 5) 2 = 4
(iii) log a (L.H.S.) = log a 
= 
....(i)
and log a (R.H.S.) = log a 
= 
log a b = 
.... (ii)
from (i) and (ii) we get 
= 
(iv) 
= 
= 
= a 2 + a + 1
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