Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The distance of the point (1, 3, – 7) from the plane passing through the point (1, –1, –1), having normal perpendicular to both the lines
=
=
and
, is
Text Solution
Verified by ExpertsThe correct answer is:
B
Sol. Let the plane be
a(x – 1) + b(y + 1) + c(z + 1) = 0
a – 2b + 3c = 0
2a – b – c = 0

5(x – 1) + 7(y + 1) + 3(z + 1) = 0
5x + 7y + 3z + 5 = 0
P(1, 3, –7)
d = 
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