Home Maths JEE - Advanced Previous Year Paper JEE-Advanced-2024-Paper-2 SECTION-3 (Maximum Marks : 24) • This sectio…
Maths JEE - Advanced Previous Year Paper JEE-Advanced-2024-Paper-2 Numeric Response
Published on: August 13, 2026

SECTION-3 (Maximum Marks : 24)

• This section contains SIX (06) questions.

• The answer to each question is a NON-NEGATIVE INTEGER.

• For each question, enter the correct integer corresponding to the answer using the mouse and the on-screen virtual numeric keypad in the place designated to enter the answer.

• Answer to each question will be evaluated according to the following marking scheme:

Full Marks If ONLY the correct integer is entered;

Zero Marks : 0 In all other cases.

To form a complete monolayer of acetic acid on of charcoal, of acetic acid was used. Some of the acetic acid remained unadsorbed. To neutralize the unadsorbed acetic acid, of solution was required. If each molecule of acetic acid occupies surface area on charcoal, the value of is ………… [Use given data : Surface area of charcoal Avogadro's number ]

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Text Solution

Verified by Experts
The correct answer is:
2500

(2500)

Number of moles of unabsorbed

Number of moles of adsorbed

Surface area occupied by one molecule of

As per question

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