Published by:
CGP EDU Academic Team
Published on: August 11, 2026
If 
is any complex number satisfying 
, then the minimum value of 
is 
. (IIT-JEE, 2011)
Text Solution
Verified by ExpertsThe correct answer is:
5
(5)
lies on or inside the circle radius 2 and center 
(minimum distance of any point on the circle to the point (3, -5/2)
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