Consider a quadratic expression
(i) If
can take both positive and negative values then
must lie in the interval
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i)
can take both positive and negative values
A quadratic
takes both positive and negative values if it has real roots, i.e., discriminant
, and
.
Here:

Step 1: 
Step 2: Discriminant 

Compute step by step:



Also,
(otherwise it's not a quadratic)
So 
(ii) For
to be non-negative for all non-negative
, we analyze two main conditions based on the graph's behavior:
Check boundary
:
The value at
must be non-negative:
.
Case 1: No real roots (
):
If the parabola never crosses the x -axis and
with
, it remains nonnegative everywhere.

Case 2: Real roots
but not in the positive domain:
If roots exist, they must both be negative or zero so that for
, the function remains
.
For roots to be negative, the sum of roots
must be negative and the product
must be positive.
Sum < 0:
.
Product
or
.
Combining these with
gives the interval
.
Combined Solution:
Joining
and
results in the final interval
.
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