Arrange the order of 
bond length in the following compounds:
Methanol Phenol p-Ethoxyphenol
Text Solution
Verified by ExpertsB
In methanol, there is no resonance. In phenol, there is resonance. In p-Ethoxyphenol, there is resonance involved but the involvement of lone pair of oxygen in 
group is poor as compared with phenol due to the presence of lone pair oxygen in 
group which are also involved in resonance.
So, partial double bond character develops in 
bond of phenol and 
-Ethoxyphenol but in case of p-Ethoxyphenol, resonance is poor as compared to phenol. So, bond length follows the order: 
──────────────────────────────────────────────────────────────────────────────────────────
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems