Published by:
CGP EDU Academic Team
Published on: August 21, 2026
In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6 Hz. When tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be:
Text Solution
Verified by ExpertsThe correct answer is:
Given that,
Difference of f A and f B , 
f = 6 Hz
If tension decreases, 
decreases and becomes f’b.
Now, difference of f A and f B , 
f '= 7 Hz
f A - f B = 6 Hz
Now, since f A = 530 Hz
f B = 524 Hz
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