A body of uniform cross-sectional area floats in a liquid of density thrice its value. The fraction of exposed height will be:
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
Here area is uniform, so portion of immersed height = 
(Here: the ratio of density of body and density of water = 
)
Therefore, fraction of exposed height will 1 – 
= 
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