The fraction of a floating object of volume V 0 and density d 0 above the surface of a liquid of density d will be
Text Solution
Verified by ExpertsThe correct answer is:
C
For the floatation, V 0 d 0 g = V in d g
⇒ V in = V 0 
∴ V out = V 0 – V in = V 0 – V 0 
⇒ 
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