A ball of mass 0.5 kg is dropped from the height of 10m. The height, at which the magnitude of velocity becomes equal to the magnitude of acceleration due to gravity, is...............m. (Use g = 10 m/s 2 ).
Text Solution
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CHECK THE SOLUTION
(5)
v 2 = u 2 + 2as
100 = 0 + 2(10)s
S=5m
Height from ground = 10 - 5 = 5m
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