Two balls A and B are placed at the top of 180 m tall tower. Ball A is released from the top at t = 0 s. Ball B is thrown vertically down with an initial velocity 'u' at t = 2 s. After a certain time, both balls meet 100 m above the ground. Find the value of 'u' in ms -1 . [use g = 10 ms -2 ] :
Text Solution
Verified by ExpertsThe correct answer is:
D
Let they meet at time t.
= 4 sec
Time taken by ball B to meet A = 2 sec
using S = ut+ 
at 2
U = 30
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