In a Carnot engine, low temperature of reservoir (sink) is 7°C. Its efficiency is 50%. To increase efficiency to 70% by how much temperature of source is to be raised, keeping the temperature of sink constant.
Text Solution
Verified by ExpertsThe correct answer is:
D
Initially 
⇒ 
⇒ 
⇒ Finally, 
0.7= 
⇒ T 1 '=933K
Increase in temperature = 933-560 = 373K
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