A beam of light consisting of two wavelengths, 6500 Å and 5200 Å is used in double slit experiment (1 Å = 10 –10 m). The distance between the slits is 2.0 mm and the distance between the plane of the slits and the screen is 120 cm.
Text Solution
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1.17 mm. 1.56 mm
Sol. Clearly 3 rd bright fringe will be at y = 3 β .
= 
= 
= 0.117 cm. = 1.17 mm.
Say m th bright fringe of 6500 Å coincides with n th bright fringe of 5200 Å .
⇒ n β 1 = m β 2
⇒ 
= 
Hence, for least distance, 5 th bright fringe of 5200 Å coincides with 4 th bright fringe of 6500 Å.
⇒ y’ = 4 β 1 = 
= 0.156 cm = 1.56 mm
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