Published by:
CGP EDU Academic Team
Published on: September 11, 2026
A slit of width ‘a’ is illuminated by light of wavelength 6000 A 0 For What value of ‘a will the :-
(i) First maximum fall at an angle of diffraction of 30 0 ?
(ii) First minimum fall at an angle of diffraction 30 0 ?
Correct Matrix Matching
Text Solution
Verified by ExpertsThe correct answer is:
(i)1; (ii)1; (i) For first maximum sin ; (ii) For first minimum sin
(i)1.8 μ m (ii)1.2 μ m
Sol. (i) For first maximum
sin θ m = 
sin θ 1 = 
or a =
=
= 1.8 μ m
(ii) For first minimum
sin θ m = 
or sin θ 1 = 
a = 
a =
= 1.2 μ m
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Two coherent sources produce waves of different intensities which interfere. After interference, th…
<p>In Young's double slit experiment, the slits are placed 0.320 mm apart. Light of wavelength λ = …
In a double-slit experiment, green light (5303Å) falls on a double slit having a separation of 19.4…
Consider a tank made of glass (refractive index 1.5) with a thick bottom. It is filled with a liqui…
Visible light of wavelength falls normally on single slit and produces a diffraction pattern. It i…
A polarizer - analyser set is adjusted such that the intensity of light coming out of the analyser …