A double slit interference experiment performed with a light of wavelength 600 nm forms
an interference fringe pattern on a screen with 10 th bright fringe having its centre at a distance of 10 mm from the central maximum. Distance of the centre of the same 10th bright fringe from the central maximum when the source of light is replaced by another source of wavelength 660 nm would be mm.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(11) Position of the
bright fringe w.r.t. central maxima in a YDSE is
.
or

Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A monochromatic light of frequency travelling through air, is incident on a medium of refractive i…
Width of one of the two slits in a Young's double slit interference experiment is half of the other…
Two monochromatic light beams have intensities in the ratio . An interference pattern is obtained …
In a Young's double slit experiment, the slits are separated by 0.2 mm. If the slits separation is …
In a Young's double slit experiment, two slits are located 1.5 mm apart. The distance of screen fro…
Two polarizers and are placed in such a way that the intensity of the transmitted light will be z…