Published by:
CGP EDU Academic Team
Published on: September 12, 2026
In a Young's double slit experiment, two slits are located 1.5 mm apart. The distance of screen from slits is 2 m and the wavelength of the source is 400 nm. If the 20 maxima of the double slit pattern are contained within the central maximum of the single slit diffraction pattern, then the width of each slit is 
, where 
-value is_____.
Text Solution
Verified by ExpertsThe correct answer is:
15
(15)
Width of 20 maxima of double slit 
width of central maxima of single slit
Value of 
is 15
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
In young's double slit experiment performed using a monochromatic light of wavelength , when a gla…
Using Young's double slit experiment, a monochromatic light of wavelength 5000 produces fringes of…
In Young's double slit experiment the two slits are 0.6 mm distance apart. Interference pattern is …
In a Young's double slit experiment, an angular width of the fringe is 0.35° on a screen placed at …
In a double slit experiment with monochromatic light, fringes are obtained on a screen placed at so…
A fringe width of was produced for two slits separated by apart. The screen is placed away.The w…