Chemistry Some Basic Concepts of Chemistry Atomic, Molecular and Equivalent Masses Numeric Response
Published on: August 14, 2026

At the higher temperature bleaching powder

disproportionate to some extent and yield Ca(ClO 3 ) 2 and CaCl 2 . The 10 gm of a pyrollusite sample of 26.1% purity is warmed with 240 ml of 0.5 (M) HCl, the Cl 2 (g) so produced is passed through 3.74 gm of slaked lime (hydrated CaO) containing 40% moisture at 40ºC to produce bleaching powder. The bleaching powder so produced is the "moist bleaching powder". To produce "dry bleaching powder" the "moist bleaching powder" is heated at 80ºC where Ca(OCl)Cl disproportionate to some extent. "Dry bleaching powder" so produced is divided into two equal parts.

To the first part excess of HCl and excess of KI solution added I 2 so produced require 300 ml of 10 –3 (M) Na 2 S 2 O 3 solution.

To the second part excess of CH 3 COOH and excess of KI solution is added the iodine so produced require 200 ml of 10 –3 (M) Na 2 S 2 O 3 solution. It is also seen during drying of moist bleaching powder beside

disproportionation of Ca(OCl)Cl other side reactions also occur "without any gaseous products."

At. wts Mn= 55; Ca = 40

(i) The mass of moist bleaching powder sample

produced is –

A
5.87 gm 55.9% There is no definite reason it was an experimental error
B
5.306 gm 0.638% In the first part both I 2 and Cl 2 consume Na 2 S 2 O 3 solution whereas for second part only I 2 consume Na 2 S 2 O 3 solution.
C
3.81 gm 75.7 % For the Ist part in the presence of excess HCl, Ca(ClO 3 ) 2 also liberate Cl 2 which require excess of Na 2 S 2 O 3 solution whereas for the second part only Ca(OCl) Cl liberate Cl 2 .
D
4.67 gm (ii) What is the percentage of available chlorine in the "dry bleaching powder" ? 0.32% (iii)What is the reason for the differences in the volume of Na 2 S 2 O 3 solution for the two equal part of the dry bleaching powder sample? None of these

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Text Solution

Verified by Experts
The correct answer is:
5.87

(i)

Sol. 5.87 gm

(ii)

Sol. 0.638%

(iii)

Sol. For the Ist part in the presence of excess HCl, Ca(ClO 3 ) 2 also liberate Cl 2 which require excess of Na 2 S 2 O 3 solution whereas for the second part only Ca(OCl) Cl liberate Cl 2 .

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