Molarity, molality, mole fraction are used in these days for stoichiometric calculations. It is necessary to write balanced chemical equation when calculations are done in terms of molarity.
(i)38% HCl has density equal to 1.20 g ml –1 . The molality and molarity respectively are –
Text Solution
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(i)
Sol. M = 
× 
= 
= 
= 
= 
= 12.49 M
m = 
= 
× 
=
= 16.7 mol/kg or 16.7 molal
(ii)
Sol. BaCl 2 + K 2 SO 4 → BaSO 4 + 2KCl
No. of moles of BaCl 2 = 
= 0.01 moles
No. of moles of K 2 SO 4 = 
= 
= 0.0025 moles
K 2 SO 4 is limiting reactant
0.0025 moles of K 2 SO 4 reacts with 0.0025 moles of BaCl 2 to form 0.0025 moles of BaSO 4 .
(iii)
Sol. x B = 0.2
x B = 
⇒ 
= 
+ 
= n B
= 
n B = 
× 
n B = 
⇒ n B = 13.88 M
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