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CGP EDU Academic Team
Published on: August 14, 2026
How many unit cells are present in a cube-shaped ideal crystal of NaCl of mass 1.00g? [Atomic masses : Na = 23, Cl = 35.5]
Text Solution
Verified by ExpertsThe correct answer is:
A
mass (m) = density × volume = 1.00 g
Mol. wt. (M) of NaCl = 23 + 15.5 = 58.5
Number of unit cells present in a cube shaped crystal of NaCl of
mass 1.00 g = 
(In NaCl each unit cells has 4 NaCl units. Hence Z = 4)
∴ Number of unit cells = 0.02573 × 1023 = 2.57 × 1021 unit cells.
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