For a homogeneous gaseous phase reaction : 2A ⎯→ 3B + C, the initial pressure of reactant was P° while pressure at time 't' was P. Find pressure after time 2t. Assume I order reaction.
Text Solution
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2A → 3B + C
Initial pressure Pº 0 0
Pressure at t = t Pº –2a 3a a
Pressure at t = 2t Pº –2x 3x x
Given Pº – 2a + 3a + a = P
∴ Pº + 2a = P …..(1)
Now for I order reaction at time t
K = 
……(2)
Let total pressure at t = 2t be A, then Pº –2x + 3x + x =
A or Pº + 2x = A
……. (3)
…….. (4)
By Eqs. (2) and (4) 
[2Pº – A] . Pº = [2Pº – P] 2 ∴ Pº. A= 2 (Pº)
2 – (2Pº – P) 2 ∴ A = 2Pº 
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