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CGP EDU Academic Team
Published on: August 13, 2026
The inversion of cane sugar proceeds with constant half life of 500 minute at pH = 5 for any concentration of sugar. However, if pH = 6, the half life changes to 50 minute. Derive the rate law for inversion of cane sugar.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
At pH = 5,the half life is 500 for all concentrations of sugar. i.e. t 1/2 ∝ [sugar] 0 . Thus, the reaction is I order w.r.t sugar.
Now rate = K[sugar] 1 [H + ] m Also for [H
+ ] t 1/2 ∝ [H + ] 1– m ∴ 500 ∝ [10
–5 ] 1– m
50 ∝ [10 –6 ] 1 – m ∴ 10 = (10) 1– m or 1 – m = 1 ∴ m = 0
Therefore , rate = K [sugar]
1 [H + ] 0 .
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