Published by:
CGP EDU Academic Team
Published on: August 12, 2026
Which is/are correct statements :
A
When 100 ml of 0.1 M NaCN solution is titrated with 0.1 M HCl solution the variation of pH of solution with volume of HCl added will be (as shown in figure): 
A & C
A & C
B
Variation of degree of dissociation a with concentration for a weak electrolyte at a particular temperature is best represented by (as shown in figure) : 
B & C
B & C
C
0.1 M acetic acid solution is titrated against 0.1 M NaOH solution. The difference in pH between 1/4 and 3/4 stages of neutralization of acid will be 2 log 3. A, B & C
D
B only
Text Solution
Verified by ExpertsThe correct answer is:
C
Initially pH will decrease fast, then slowly due to buffer formation and then will decrease fast as buffer action diminishes.
For a weak electrolyte
Ka = 
when α << 1 then α = 
as C increases
α decreases
as C is tending to zero 
α will be unity
At 1/4th neutralization
CH3COOH + NaOH 
CH3COONa + H2O
pH = pKa + log 
= pKa + log 
At 3/4th neutralization
pH = pKa + log 3
so difference in pH = Δ (pH) = log 3 – log = 2 log 3
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