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CGP EDU Academic Team
Published on: August 13, 2026
To a 200 ml of 0.1 M weak acid HA solution 90 ml of 0.1 M solution of NaOH be added. Now, what volume of 0.1 M NaOH be added into above solution so that pH of resulting solution be 5. [(Ka(HA) = 10–5]
Text Solution
Verified by ExpertsThe correct answer is:
C
HA + NAOH 
NaA + H2O
t = 0 20 9 0 0
t = t 11 0 9 0
t = 50% 10 0 10
10 ml NaOH is required.
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