Published by:
CGP EDU Academic Team
Published on: August 14, 2026
One mole of an ideal diatomic gas (Cv = 5 cal) was transformed from initial 25 0 C and 1 L to the state when temperature is 100 0 C and volume 10 L. Then for this process(R = 2 calories/mol/K) (take calories as unit of energy and kelvin for temp)
A
H = 525
B
S = 5 ln + 2 ln 10
C
E = 525
D
G of the process cannot be calculated using given information.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, b, d)
S = nCV ln 
+ nR ln 
= 5 ln 
+ 2 ln 10
H = nCP 
T = n (CV+ R) 
T = 1 × 7 ´ 75 = 525 cal
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