Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The enthalpy of vapourisation of water = 45.953 kJ/mol. At 1 atm pressure the boiling point of water is 373 K. What is the boiling point of water when pressure equal to ½ atm in Kelvin in nearest possible integers? Given : log 2 = 0.3
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
0356
Sol. log 
= 
log 
= 
= 2.4 × 10 3 × 
p 2 = 
atm, p 1 = 1 atm
log 
= 2.4 × 10 3 × 
= – log 2
∴ 2.4 × 10 3 × 
= – 0.3
– 
= – 
× 10 –3
= – 0.125 × 10 –3
or 
+ 0.125 × 10 –3 = 
or 
= 2.681 × 10 –3 + 0.125 × 10 –3
= 2.806 × 10 –3 or T 2 = 
= 356.38 K ~ 356 K
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
If
then the possible heat of methane will be
Molar heat of vaporisation of a liquid is . If the entropy change is , the boiling point of the l…
The enthalpy of fusion of ice per mole
In which of the following neutralisation reactions, the heat of neutralisation will be highest
If
then the enthalpy of formation of at 298K will be
From Kirchhoff's equation which factor affects the heat of reaction