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Chemistry Electrochemistry General Single Correct MCQ
Published on: August 13, 2026

The driving force Δ G diminishes to zero on the way to equilibrium, just as in any other spontaneous process. Both Δ G and the cell potential are zero when the redox reaction comes to equilibrium. The Nernst equation for the redox process of the cell may be given as :

E = Eº – log10Q

The key to the relationship is the standard cell potential Eº, derived from the standard free energy change as :

Eº =

At equilibrium, the Nernst equation is given as :

Eº = log10K

(i)On the basis of information available for the reaction Al + O2 ⎯→ Al2O3; Δ G = –827 kJ/mol of O2 the minimum emf required to carry out an electrolysis of Al2O3 is –

(Given : 1 F = 96500 C)

A
2.14 V E = Eº Straight line antilog 15.6 10–37
B
4.28 V RT/nF = 1 Parabola antilog 2.5 1037
C
6.42 V E = 0 Hyperbola antilog 1.5 10–39
D
8.56 V (ii) The equilibrium constant Kc will be equal to Q when – Eº = 1 (iii) The nature of graph of Eºcell against log Kc is a/an – Elliptical curve (iv) The equilibrium constant Kc for the reaction: Cu(s) + 2Ag+(aq) Cu2+(aq) + 2Ag(s) (Eºcell = 0.46V) will be – antilog 12.2 (v) Eº for the electrochemical cell, Zn(s) |Zn2+ (1 M) aq || Cu2+ (1 M) aq| Cu(s) is 1.10 volt at 25ºC. The equilibrium constant for the cell reaction: Zn(s) + Cu2+ (aq) Cu(s) + Zn2+(aq) will be – 1039

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Text Solution

Verified by Experts
The correct answer is:
B

(i)

Sol. 2.14 V

(ii)

Sol. E = 0

(iii)

Sol. straight line

(iv)

Sol. antilog 15.6

(v)

Sol. 1037

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