The standard reduction potential of some half reactions are given belows
Cu +2 + e – → Cu + ; E° 1 = 0.15 volt
Cu + + e – → Cu; E° 2 = 0.50 volt
Ag + + e – → Ag = E° 3 = 0.799 volt
The decrease in gibb's free energy is responsible for the production of equivalent amount of electrical work.
(i) The E° cell for Cu/Cu +2 in volt is –
Text Solution
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(i)
Sol. Cu +2 + e – → Cu + ; Δ G° 1 = –1 × F × E° 1
Cu + e – → Cu ; Δ G° 2 = – 1 × F × E° 2
Cu +2 → Cu ; Δ G° 3 = –2 × F × E° 3
Δ G° 3 = Δ G° 1 + Δ G° 2
–2 × F × E° 3 = –F × (0.15) – F(0.50)
E° 3 = 0.325 volt
(ii)
Sol. E° cell = E° cathode – E°anode
= E° Ag + |Ag – E° Cu +2 |Cu
= 0.799 – 0.325
= 0.474 volt
(iii)
Sol. For two isotonic solution ;
= 
iCRT = iCRT
= (iC) glucose
[ α (n–1)+1].C = i × C
[ α (3–1)+1]0.004 = 1 × 0.01
α = 0.75 = 75%
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