Published by:
CGP EDU Academic Team
Published on: August 11, 2026
Complete the following reaction:
(i) TiCl 4 + BCl 3 + H 2 
.....
A
...... + HCl (ii) BCl 3 + NH 4 Cl 
B
(iii) BCl 3 + H 2 (g) 
C
(iv) BCl 3 + H 2 + C(fibre) 
D
(v) Na 2 B 4 O 7 + NH 4 Cl 
(E) (vi) BF 3 
(F) (vii) BCl 3 
(G)
(E) (vi) BF 3 (F) (vii) BCl 3 (G)
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(i) = TiB 2 titanium borides
(ii) = B 3 N 3 H 3 Cl 3 ;
(iii) 2BCl 3 + 3H 2 
2B + 6HCl
(Crystalline B)
(vi) D ≡ B 4 C
(v) Na 2 B 4 O 7 + 2NH 4 Cl ⎯→
NaCl + 2NH 3 + H 2 B 4 O 7
H 2 B 4 O 7 ⎯→ 2B 2 O 3 + H 2 O
NH 3 + B 2 O 3 ⎯→ (BN) x ; boron nitride (E)
(vi) 4BF 3 + 3H 2 O ⎯→ H 3 BO 3 + 3HBF 4 ≡ F
(gelatinous white ppt)
(vii) BCl 3 + 3HOH ⎯→ B(OH) 3 + 3HCl
white ppt (G)
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