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CGP EDU Academic Team
Published on: August 13, 2026
A solution containing 2.675 g of CoCl3 . 6 NH3 (molar mass = 267.5 g mol–1) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of AgNO3 to give 4.78 g of AgCl (molar mass = 143.5 g mol–1). The formula of the complex is (At. mass of Ag = 108 u)
Text Solution
Verified by ExpertsThe correct answer is:
A
Mole of CoCl3 . 6NH3 = 
= 0.01
AgNO3 (aq) + Cl– (aq) 
AgCl ¯ (white)
Mole of AgCl = 
= 0.03
0.01 mole of CoCl3 . 6NH3 gives 0.03 mole of AgCl
1 mole of CoCl3 . 6NH3 ionises to give 3 moles of Cl–.
Hence the formula of compound is [Co(NH3)6] Cl3 .
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