Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Element ‘B’ forms ccp structure and ‘A’ occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is:
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
B
No. of lattice points = No. of Oh voids
No. of 
voids in 
structure
No. of atoms of 
No. of atoms of 
No. of Oh voids
No. of atoms of 
No. of all Td voids
No. of lattice points
Hence, 
Therefore, the formula of the compound is 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
At 100° C, copper (Cu) has FCC unit cell structure with cell edge length of . What is the approxim…
Which primitive unit cell has unequal edge lengths and all axial angles different from 90°?
A compound of formula has the hcp lattice. Which atom forms the hcp lattice and what fraction of t…
A solid having density of forms face centred cubic crystals of edge length pm. What is the molar …
The radius of the largest sphere which fits properly at the centre of the edge of a body centred cu…
Consider the bcc unit cells of the solids 1 and 2 with the position of atoms as shown below. The ra…