The following reaction decomposes N 2 O 5 
2NO 2 + 
O 2 . At a 25 degree centigrade the rate constant of the reaction is 5 x 10 -2 sec -1 . The initial pressure of N 2 O 5 is 0.2 atm. If total pressure of gaseous mixture becomes 0.35 atm, then calculate the time of decomposition of N 2 O 5 .
Text Solution
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138.6 seconds
(i) The decomposition reaction is represented by
Total pressure = p 0 - x + 2x + 
= p 0 + 
= 0.2 atm.
or 
= 0.35 - 0.2 = 0.15
x = 0.1 atm
Pressure of N 2 O 5 after t seconds,
P = P 0 - x = (0.2 - 0.1) = 0.1 atm
Now applying first order rate law
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