CO 2 gas is liquefied at 27°C. Gas follows the following gr…

Chemistry Gaseous State ( Not In Syllabus ) NTA Abhiyas Question - Liquid and Gaseous State Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: August 13, 2026

CO 2 gas is liquefied at 27°C. Gas follows the following graph during liquefaction for 1 mole of CO 2 .

Then which statement is (are) correct in gaseous phase will

(i) The maximum density of gas is 0.1 gm/ml

(ii) The density of liquid CO 2 is 1 g/ml at 60 atm.

(iii) At point C 50% of CO 2 is liquefied.

(iv) The compressibility factor of gas at 27° C is always less than 1.

Which of the above is/are correct

only i

i and ii

i,ii and iii

all

Text Solution

Verified by Experts

The correct answer is:

i,ii and iii

Maximum density of CO 2 in gaseous phase will be at point 'A'

Now: = 107 gm/lt = 0.107 gm/cc

Density of liquid CO 2 at 60 atm (at point B)

At point B there will be only liquid CO 2 . So we can find out the density of density of liquid CO 2 only at point B.

at point C the volume will be

And pressure is same so obviously approx. half of CO 2 is liquified

Z can be greater than 1 at 27°C. For example at point 'A' Z is 1.07, So wrong.

Previous Question Next Question

Get practice questions, solutions, and test series in one place.

Share your experience with this question and solution.

Send your comment, doubt, correction, or feedback to admin.

What students say about this solution

No reviews yet. Be the first to write a review.