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CGP EDU Academic Team
Published on: August 13, 2026
At 310 K, the solubility of CaF 2 in water is 2.34 x 10 -3 g /100 mL. The solubility product of CaF 2 is___x 10 -8 (mol/L) 3 . (Given molar mass : CaF 2 = 78 g mol -1 )
Text Solution
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Solubility of CaF 2 = S mole/L
K sp (CaF 2 ) = 4S 3 =4(3x10 -4 ) 3
=108 x 10 -12
= 0.0108 x 10 -8 (mol/L) 3
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